Chapter Review
Quadratic Equations and Polynomials
Quadratic Roots · Polynomials and Synthetic Division · Partial Fractions
Quadratic Formula and the Discriminant
The quadratic formula solves any equation $ax^2 + bx + c = 0$ using the discriminant $D = b^2 - 4ac$ to determine whether roots are real, repeated, or complex.
Key Points
- •$D > 0$: two distinct real roots; if $D$ is a perfect square (rational $a,b,c$), roots are rational
- •$D = 0$: one repeated real root at $x = -b/2a$ (the vertex)
- •$D < 0$: two complex conjugate roots $p \pm qi$
- •Irrational roots come in conjugate pairs $p \pm \sqrt{q}$ when $a,b,c$ are rational
- •Always compute $D$ first before attempting to find root values
Formula
$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$
Vieta's Formulas
Vieta's formulas relate the sum and product of quadratic roots directly to the coefficients, bypassing the need to solve for individual roots.
Key Points
- •Sum of roots: $\alpha + \beta = -b/a$
- •Product of roots: $\alpha\beta = c/a$
- •For a monic quadratic ($a=1$): sum $= -b$, product $= c$
- •Construct equation from roots: $x^2 - (\alpha+\beta)x + \alpha\beta = 0$
- •$\alpha^2 + \beta^2 = (\alpha+\beta)^2 - 2\alpha\beta$
- •$|\alpha - \beta| = \sqrt{D}/|a|$
Formula
$$\alpha + \beta = -\frac{b}{a}, \quad \alpha\beta = \frac{c}{a}$$
Cube Roots of Unity
The three solutions to $x^3 = 1$ are $1, \omega, \omega^2$ where $\omega$ and $\omega^2$ are complex conjugates equally spaced at 120° on the unit circle.
Key Points
- •$\omega = \frac{-1 + \sqrt{3}i}{2}$, found from $x^2 + x + 1 = 0$
- •Sum property: $1 + \omega + \omega^2 = 0$
- •Cyclic property: $\omega^3 = 1$, so reduce exponents mod 3
- •$\omega$ and $\omega^2$ are complex conjugates of each other
- •Factorization: $x^3 - y^3 = (x-y)(x-\omega y)(x-\omega^2 y)$
Formula
$$1 + \omega + \omega^2 = 0, \quad \omega^3 = 1$$
Fourth Roots of Unity
The four solutions to $x^4 = 1$ are $\{+1, -1, +i, -i\}$, obtained by factoring $x^4 - 1 = (x^2-1)(x^2+1) = 0$.
Key Points
- •Two real roots ($\pm 1$) and two imaginary roots ($\pm i$)
- •Sum of all four roots is zero
- •Product of all four roots is $-1$ (unlike cube roots where product is $1$)
- •Spaced 90° apart on the unit circle
- •To find $\sqrt[4]{a}$: multiply each fourth root of unity by $\sqrt[4]{|a|}$
Polynomial Division Algorithm
Any polynomial $P(x)$ divided by $d(x)$ yields a quotient $Q(x)$ and remainder $R$ such that $P(x) = d(x)Q(x) + R$, with deg($R$) < deg($d$).
Key Points
- •Both polynomials must be in standard form (descending powers) before dividing
- •Dividing degree-$n$ by degree-$m$ gives quotient of degree $n-m$
- •If $R = 0$, the divisor is a factor of the dividend
- •Insert placeholder zeros for any missing powers of $x$
Formula
$$P(x) = d(x) \cdot Q(x) + R$$
Synthetic Division
Synthetic division is a streamlined coefficient-only method for dividing a polynomial by a linear factor $(x - c)$, using multiply-and-add steps.
Key Points
- •Only works for linear divisors with leading coefficient 1
- •For divisor $(x + k)$, use $c = -k$ (flip the sign)
- •Drop the leading coefficient, then repeatedly multiply by $c$ and add
- •The last number in the bottom row is the remainder; the rest are quotient coefficients
- •Insert 0 for any missing powers in the dividend
Remainder and Factor Theorems
The Remainder Theorem states $P(c)$ equals the remainder when dividing by $(x-c)$; the Factor Theorem follows as the special case where $P(c) = 0$ means $(x-c)$ is a factor.
Key Points
- •Remainder Theorem: $R = P(c)$ — evaluate instead of dividing
- •Factor Theorem: $(x-c)$ is a factor $\iff$ $P(c) = 0$
- •Use to find unknown coefficients: set $P(c) = R$ and solve
- •Depressed equation: after removing factor $(x-c)$, solve the lower-degree quotient for remaining roots
- •Repeated synthetic division reduces degree by 1 each time
Formula
$$P(c) = 0 \iff (x - c) \text{ is a factor of } P(x)$$
Partial Fractions — Distinct Linear Factors
A proper rational fraction with distinct linear factors in the denominator decomposes into a sum of simple fractions, each with a constant numerator over one linear factor.
Key Points
- •Check proper: deg(numerator) < deg(denominator); if not, long-divide first
- •Each distinct factor $(x - a_i)$ contributes $\frac{A_i}{x - a_i}$
- •Clear denominators, then substitute roots to isolate each constant
- •Cover-up shortcut: cover a factor in the denominator and evaluate the rest at that root
- •Always verify by recombining the partial fractions
Formula
$$\frac{P(x)}{(x-a)(x-b)} = \frac{A}{x-a} + \frac{B}{x-b}$$
Partial Fractions — Repeated Linear Factors
A repeated factor $(x-a)^n$ in the denominator generates $n$ partial fraction terms with ascending powers from 1 to $n$, each with a constant numerator.
Key Points
- •Cannot skip powers: $(x-a)^3$ needs terms for $(x-a)^1$, $(x-a)^2$, and $(x-a)^3$
- •Substitute $x = a$ to find the highest-power constant first
- •Use equating coefficients for the remaining constants
- •Watch for disguised repeats: e.g. $(x+1)^2(x^2-1) = (x+1)^3(x-1)$
Formula
$$\frac{P(x)}{(x-a)^n} = \frac{A_1}{x-a} + \frac{A_2}{(x-a)^2} + \cdots + \frac{A_n}{(x-a)^n}$$
Partial Fractions — Irreducible Quadratic Factors
An irreducible quadratic factor ($b^2 - 4ac < 0$) in the denominator requires a linear numerator $Ax + B$, not just a constant.
Key Points
- •Numerator degree must be one less than denominator factor degree
- •Irreducibility check: discriminant $b^2 - 4ac < 0$
- •Repeated irreducible quadratic $(ax^2+bx+c)^n$ produces $n$ terms, each with a linear numerator
- •Use substitution for linear roots first, then equate coefficients for quadratic unknowns
- •Hybrid approach: substitution + equating coefficients is most efficient
Formula
$$\frac{P(x)}{(x-r)(ax^2+bx+c)} = \frac{A}{x-r} + \frac{Bx+C}{ax^2+bx+c}$$
Formulas
Quadratic Formula
Solves any quadratic equation using coefficients a, b, c.
Formula
$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$
Discriminant
Determines nature of roots: positive → 2 real, zero → 1 repeated, negative → complex.
Formula
$$D = b^2 - 4ac$$
Vieta's — Sum and Product
Relates roots to coefficients without solving the equation.
Formula
$$\alpha + \beta = -\frac{b}{a}, \quad \alpha\beta = \frac{c}{a}$$
Cube Roots of Unity
The three cube roots of 1 sum to zero; ω³ = 1.
Formula
$$1 + \omega + \omega^2 = 0$$
Remainder Theorem
Remainder of P(x) ÷ (x−c) equals P(c).
Formula
$$R = P(c)$$
Factor Theorem
A binomial (x−c) is a factor if and only if P(c) = 0.
Formula
$$P(c) = 0 \iff (x-c) \text{ is a factor}$$
Partial Fractions — Distinct Linear
Each distinct linear factor gets a constant numerator.
Formula
$$\frac{P(x)}{(x-a)(x-b)} = \frac{A}{x-a} + \frac{B}{x-b}$$
Partial Fractions — Irreducible Quadratic
Quadratic denominator factor requires a linear numerator Ax+B.
Formula
$$\frac{Bx+C}{ax^2+bx+c}$$