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Polynomials and Synthetic Division
The Polynomial Division Algorithm
Polynomial division mirrors numerical division, relating a dividend ($P(x)$) to its divisor ($d(x)$), quotient ($Q(x)$), and remainder ($R$).
$$P(x) = d(x)Q(x) + R$$
The Division Algorithm expresses a polynomial as the product of its divisor and quotient plus any remaining value.
$P(x)$=Dividend polynomial(unitless)
$d(x)$=Divisor polynomial(unitless)
$Q(x)$=Quotient polynomial(unitless)
$R$=Remainder constant (if divisor is linear)(unitless)
$R = 0$
→The divisor is a factor of the dividend.
Standard Form: Both polynomials must be written in descending order of degree before starting.
Degree Constraint: For the algorithm to finish, the degree of the remainder must be less than the degree of the divisor.
Quotient Degree: When dividing a degree-$n$ polynomial by a degree-$m$ divisor, the quotient has degree $n - m$.
Synthetic Division: The Shortcut
Synthetic division is a streamlined method for dividing by a linear divisor of the form $x - c$, focusing solely on coefficients.
$$x - c \implies \text{Use } c \text{ in the synthetic array}$$
The constant $c$ is the value that makes the divisor zero ($x - c = 0$).
$c$=Zero of the divisor(constant)
$x - c$=Linear binomial divisor(unitless)
$x + 3$
→$c = -3$ (Always flip the sign of the constant term).
Placeholder Zero: If a power of $x$ is missing in the dividend, a $0$ must be inserted in the synthetic array.
Leading Coefficient: The first coefficient of the dividend is always dropped straight down to begin the process.
Limitation: Synthetic division only works when the divisor is linear with leading coefficient $1$. For divisors like $2x - 1$, use long division or divide all coefficients by $2$ first.
The Remainder and Factor Theorems
The Remainder Theorem allows calculating $P(c)$ without division, while the Factor Theorem identifies roots where the remainder is zero.
$$P(c) = R$$
Evaluating a function at $c$ gives the same result as the remainder of $P(x) \div (x - c)$.
$P(c)$=Polynomial evaluated at $c$(value)
$R$=Remainder from division(value)
$P(c) = 0$
→$(x - c)$ is a factor and $c$ is a root.
Synthetic Substitution: Using synthetic division to find $P(c)$ is often faster than direct substitution for high-degree polynomials.
Zero of a Function: If $(x - c)$ is a factor, then $x = c$ is an x-intercept on the graph of $P(x)$.
Converse Direction: The Factor Theorem works both ways — $P(c) = 0$ proves $(x - c)$ is a factor, and $(x - c)$ being a factor proves $P(c) = 0$.
Finding Unknown Coefficients: Set $P(c) = R$ (given remainder) to build equations for unknown parameters like $k$ or $p$.
Depressed Equations and Complete Factoring
When a known root $c$ is used in synthetic division, the quotient polynomial (one degree lower) is called the depressed equation. Solving it finds the remaining roots.
$$P(x) = (x - c) \cdot Q(x) \implies \text{solve } Q(x) = 0$$
After removing one factor via synthetic division, the depressed equation $Q(x) = 0$ contains the remaining roots.
$Q(x)$=Depressed polynomial (quotient after division)(unitless)
$(x - c)$=Factor corresponding to known root $c$(unitless)
Multiple known roots
→Apply synthetic division repeatedly — each division reduces the degree by 1.
Depressed equation is quadratic
→Factor directly or use the quadratic formula to find remaining roots.
Degree Reduction: A degree-$n$ polynomial with $k$ known roots requires synthetic division $k$ times, leaving a degree-$(n - k)$ depressed equation.
Order Independence: Multiple synthetic divisions can be performed in any order — the final depressed equation is the same.
Forming Polynomial Equations from Roots
Given all roots of a polynomial, the equation can be reconstructed by multiplying the corresponding linear factors together.
$$P(x) = (x - r_1)(x - r_2) \cdots (x - r_n)$$
Each root $r_i$ contributes a factor $(x - r_i)$. Their product gives the complete polynomial.
$r_1, r_2, \ldots, r_n$=The $n$ roots of the polynomial(unitless)
$(x - r_i)$=Linear factor for root $r_i$(unitless)
Quadratic ($n = 2$)
→$x^2 - (r_1 + r_2)x + r_1 r_2 = 0$, i.e., $x^2 - Sx + P = 0$ where $S$ = sum and $P$ = product of roots.
Sum and Product Shortcut: For a quadratic with roots $\alpha, \beta$: the equation is $x^2 - (\alpha + \beta)x + \alpha\beta = 0$.
Scaling: Any constant multiple $k \cdot P(x) = 0$ has the same roots. The leading coefficient can be chosen freely.